Nessie is quite right that Mattogno is out of his depths for at least some of this. Look at this doozy:
LOL! He is of course referring to output power. The output power of the motor was changed from 2 hp to 3.5 hp. He mentions that the input frequency of the electric input stays at 50 Hz and therefore the rpm can't change!!!!!! ROFLMAO!Mattogno wrote:The invoices of the Topf Company no. 171 of February 22nd 1943, and no. 729 of May 27, 1943, refer explicitly to the frequency of 50 periods or cycles, that is 50 Hz. Therefore, increasing the power output of the motor, from 2 to 3.5 HP, the number of the revolutions would have remained unchanged.
For Mattogno's (or anyone else's) information, the way to view the output power is as:
P = T * w
T = torque of motor
w = angular velocity of shaft
The actual input electricity would be the same for any and all electric motors that we are talking about here (3-phase 380V motor - at 50 Hz of course) . The torque of the motor is what spins the motor - causing the rotational velocity. An increase of the output power would necessarily entail that you desired a higher rpm. You sure as hell wouldn't increase the power for any other reason. I suppose one could imagine a much heavier motor which would require greater torque to move it at the same rpm; but Mattogno doesn't mention anything like that. He brings up the input frequency!
In general, it is most logical that a motor rated with a higher output power, all other things more or less equal, means a greater output rpm - no matter what kind of electrical motor we are talking about in this instance. Both motors are obviously blower motors for ventilation. If we were comparing, say, automobile engine motors to fan motors what I say would not be correct; but we aren't doing that.
That Mattogno goes through all of the BS in that article to not understand such a simple thing shows just how far out of his depth he is! And the way in which he shows this is pretty funny!